Symmetric Positive Semidefinite Matrices of Fixed Rank

Manifolds.SymmetricPositiveSemidefiniteFixedRank โ€” Type
SymmetricPositiveSemidefiniteFixedRank{T,๐”ฝ} <: AbstractDecoratorManifold{๐”ฝ}

The AbstractManifold $\operatorname{SPS}_k(n)$ consisting of the real- or complex-valued symmetric positive semidefinite matrices of size $nร—n$ and rank $k$, i.e. the set

\[\operatorname{SPS}_k(n) = \bigl\{ p โˆˆ ๐”ฝ^{nร—n}\ \big|\ p^{\mathrm{H}} = p, apa^{\mathrm{H}} \geq 0 \text{ for all } a โˆˆ ๐”ฝ \text{ and } \operatorname{rank}(p) = k\bigr\},\]

where $โ‹…^{\mathrm{H}}$ denotes the Hermitian, i.e. complex conjugate transpose, and the field $๐”ฝ โˆˆ \{ โ„, โ„‚\}$. We sometimes $\operatorname{SPS}_{k,๐”ฝ}(n)$, when distinguishing the real- and complex-valued manifold is important.

An element is represented by $q โˆˆ ๐”ฝ^{nร—k}$ from the factorization $p = qq^{\mathrm{H}}$. Note that since for any unitary (orthogonal) $A โˆˆ ๐”ฝ^{nร—n}$ we have $(Aq)(Aq)^{\mathrm{H}} = qq^{\mathrm{H}} = p$, the representation is not unique, or in other words, the manifold is a quotient manifold of $๐”ฝ^{nร—k}$.

The tangent space at $p$, $T_p\operatorname{SPS}_k(n)$, is also represented by matrices $Y โˆˆ ๐”ฝ^{nร—k}$ and reads as

\[T_p\operatorname{SPS}_k(n) = \bigl\{ X โˆˆ ๐”ฝ^{nร—n}\,|\,X = qY^{\mathrm{H}} + Yq^{\mathrm{H}} \text{ i.e. } X = X^{\mathrm{H}} \bigr\}.\]

Note that the metric used yields a non-complete manifold. The metric was used in [JBAS10][MA20].

Constructor

SymmetricPositiveSemidefiniteFixedRank(n::Int, k::Int, field::AbstractNumbers=โ„; parameter::Symbol=:type)

Generate the manifold of $nร—n$ symmetric positive semidefinite matrices of rank $k$ over the field of real numbers โ„ or complex numbers โ„‚.

source
Base.exp โ€” Method
exp(M::SymmetricPositiveSemidefiniteFixedRank, q, Y)

Compute the exponential map on the SymmetricPositiveSemidefiniteFixedRank, which just reads

\[ \exp_q Y = q+Y.\]

Note

Since the manifold is represented in the embedding and is a quotient manifold, the exponential and logarithmic map are a bijection only with respect to the equivalence classes. Computing

\[ q_2 = \exp_p(\log_pq)\]

might yield a matrix $q_2\neq q$, but they represent the same point on the quotient manifold, i.e. $d_{\operatorname{SPS}_k(n)}(q_2,q) = 0$.

source
Base.log โ€” Method
log(M::SymmetricPositiveSemidefiniteFixedRank, q, p)

Compute the logarithmic map on the SymmetricPositiveSemidefiniteFixedRank manifold by minimizing $\lVert p - qY\rVert$ with respect to $Y$.

Note

Since the manifold is represented in the embedding and is a quotient manifold, the exponential and logarithmic map are a bijection only with respect to the equivalence classes. Computing

\[ q_2 = \exp_p(\log_pq)\]

might yield a matrix $q_2โ‰ q$, but they represent the same point on the quotient manifold, i.e. $d_{\operatorname{SPS}_k(n)}(q_2,q) = 0$.

source
ManifoldsBase._isapprox โ€” Method
isapprox(M::SymmetricPositiveSemidefiniteFixedRank, p, q; kwargs...)

test, whether two points p, q are (approximately) nearly the same. Since this is a quotient manifold in the embedding, the test is performed by checking their distance, if they are not the same, i.e. that $d_{\mathcal M}(p,q) \approx 0$, where the comparison is performed with the classical isapprox. The kwargs... are passed on to this accordingly.

source
ManifoldsBase.check_point โ€” Method
check_point(M::SymmetricPositiveSemidefiniteFixedRank, q; kwargs...)

Check whether q is a valid manifold point on the SymmetricPositiveSemidefiniteFixedRank M, i.e. whether p=q*q' is a symmetric matrix of size (n,n) with values from the corresponding AbstractNumbers ๐”ฝ. The symmetry of p is not explicitly checked since by using q p is symmetric by construction. The tolerance for the symmetry of p can and the rank of q*q' be set using kwargs....

source